Et display med syv segmenter kan brukes til å vise tall. Gitt en rekke n naturlige tall. Oppgaven er å finne tallet i matrisen som bruker minimum antall segmenter for å vise tallet. Hvis flere tall har et minimum antall segmenter, gis det nummeret som har den minste indeksen.
Eksempler:
Inndata: arr[] = { 1 2 3 4 5 }.
Utgang: 1
Forklaring: Elementet som bruker minimum antall segmenter er 1 (dvs. 2 segmenter)Inndata: arr[] = { 489 206 745 123 756 }.
Utgang: 745
Forklaring: Elementet med minste indeks som bruker minimum antall segmenter er 745 (dvs. 12 segmenter)
Ideen er å forhåndsberegne antall segmenter som brukes av sifre fra 0 til 9 og lagre det. Summen for hvert element i matrisen nå antallet segmenter som brukes av hvert siffer. Finn deretter elementet som bruker minimum antall segmenter.
C++Antall segmenter brukt av siffer:
0 -> 6
1 -> 2
2 -> 5
3 -> 5
4 -> 4
5 -> 5
6 -> 6
7 -> 3
8 -> 7
9 -> 6
#include
import java.io.*; class GFG { // Precomputed values of segment // used by digit 0 to 9. static int []seg = { 6 2 5 5 4 5 6 3 7 6}; // Return the number of segments used by x. static int computeSegment(int x) { if (x == 0) return seg[0]; int count = 0; // Finding sum of the segment used by // each digit of a number. while (x > 0) { count += seg[x % 10]; x /= 10; } return count; } static int elementMinSegment(int []arr int n) { // Initialising the minimum segment // and minimum number index. int minseg = computeSegment(arr[0]); int minindex = 0; // Finding and comparing segment used // by each number arr[i]. for (int i = 1; i < n; i++) { int temp = computeSegment(arr[i]); // If arr[i] used less segment then update // minimum segment and minimum number. if (temp < minseg) { minseg = temp; minindex = i; } } return arr[minindex]; } static public void main (String[] args) { int []arr = {489 206 745 123 756}; int n = arr.length; System.out.println(elementMinSegment(arr n)); } }
# Precomputed values of segment # used by digit 0 to 9. seg = [6 2 5 5 4 5 6 3 7 6] # Return the number of # segments used by x. def computeSegment(x): if(x == 0): return seg[0] count = 0 # Finding sum of the segment # used by each digit of a number. while(x): count += seg[x % 10] x = x // 10 return count # function to return minimum sum index def elementMinSegment(arr n): # Initialising the minimum # segment and minimum number index. minseg = computeSegment(arr[0]) minindex = 0 # Finding and comparing segment # used by each number arr[i]. for i in range(1 n): temp = computeSegment(arr[i]) # If arr[i] used less segment # then update minimum segment # and minimum number. if(temp < minseg): minseg = temp minindex = i return arr[minindex] # Driver Code arr = [489 206 745 123 756] n = len(arr) # function print required answer print(elementMinSegment(arr n)) # This code is contributed by # Sanjit_Prasad
using System; class GFG{ // Precomputed values of segment // used by digit 0 to 9. static int []seg = new int[10]{ 6 2 5 5 4 5 6 3 7 6}; // Return the number of segments used by x. static int computeSegment(int x) { if (x == 0) return seg[0]; int count = 0; // Finding sum of the segment used by // each digit of a number. while (x > 0) { count += seg[x % 10]; x /= 10; } return count; } static int elementMinSegment(int []arr int n) { // Initialising the minimum segment // and minimum number index. int minseg = computeSegment(arr[0]); int minindex = 0; // Finding and comparing segment used // by each number arr[i]. for (int i = 1; i < n; i++) { int temp = computeSegment(arr[i]); // If arr[i] used less segment then update // minimum segment and minimum number. if (temp < minseg) { minseg = temp; minindex = i; } } return arr[minindex]; } static public void Main() { int []arr = {489 206 745 123 756}; int n = arr.Length; Console.WriteLine(elementMinSegment(arr n)); } }
// Precomputed values of segment // used by digit 0 to 9. let seg = [ 6 2 5 5 4 5 6 3 7 6]; // Return the number of segments used by x. function computeSegment(x) { if (x == 0) return seg[0]; let count = 0; // Finding sum of the segment used by // each digit of a number. while (x > 0) { count += seg[x % 10]; x = parseInt(x / 10 10); } return count; } function elementMinSegment(arr n) { // Initialising the minimum segment // and minimum number index. let minseg = computeSegment(arr[0]); let minindex = 0; // Finding and comparing segment used // by each number arr[i]. for(let i = 1; i < n; i++) { let temp = computeSegment(arr[i]); // If arr[i] used less segment then update // minimum segment and minimum number. if (temp < minseg) { minseg = temp; minindex = i; } } return arr[minindex]; } // Driver code let arr = [ 489 206 745 123 756 ]; let n = arr.length; console.log(elementMinSegment(arr n));
Produksjon
745
Tidskompleksitet: O(n * log 10 n)
Hjelpeområde: O(10)